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Question: The \({K_a}\) value for the acid \(HA\) is \(1.0 \times {10^{ - 6}}\) . What is the value of K for t...

The Ka{K_a} value for the acid HAHA is 1.0×10−61.0 \times {10^{ - 6}} . What is the value of K for the following reaction?
A++H3O↔HA+H2O{A^ + } + {H_3}O \leftrightarrow HA + {H_2}O
A.1.0×10−81.0 \times {10^{ - 8}}
B.1.0×1081.0 \times {10^8}
C.1.0×10−31.0 \times {10^{ - 3}}
D.1.0×10−61.0 \times {10^{ - 6}}

Explanation

Solution

An enormous Ka{K_a} esteem demonstrates a solid corrosive since it implies the corrosive is to a great extent separated into its particles. An enormous Ka{K_a} esteem likewise implies the development of items in the response is supported. A little Ka{K_a} esteem implies little of the corrosive separates, so you have a powerless corrosive. Powerless acids have a pKap{K_a} going from 2-1

Complete step by step answer:
Given-
Estimation of Ka{K_a} for the corrosive HA is = 1.0×10−61.0 \times {10^{ - 6}}
Response of corrosive HAHA is
HA+H2O↔H3O+A−HA + {H_2}O \leftrightarrow {H_3}O + {A^ - }
Ka{K_a} for this response is 10−6{10^{ - 6}}
Another response is -
A−+H3O+↔HA+H3O{A^ - } + {H_3}{O^ + } \leftrightarrow HA + {H_3}O
From above responses it is exceptionally certain that
K−=1Ka{K^ - } = \dfrac{1}{{{K_a}}}
Then we get 1×10−61 \times {10^-6}
And hence option D is the correct answer.

Additional information
Ka{K_a} , the corrosive ionization consistent, is the harmony steady for substance responses including frail acids in fluid arrangement. The greater the Ka{K_a} value the more it is corrive and the less Ka{K_a} value then it is more vulnerable. For a substance condition of the structure
HA+H2O↔H3O+A−(3)HA + {H_2}O \leftrightarrow {H_3}O + {A^ - }(3)
Where,
HAHA is the undissociated corrosive and
A−{A^ - } is the form base of the corrosive.

Note:
The amount pH, or "intensity of hydrogen," is a mathematical portrayal of the acidity or basicity of an answer. Arrangements with low pH are the most acidic, and the high pH are generally fundamental.