Question

The IUPAC nomenclature for the complex $Na[PtBrCl(N{{O}_{2}})(N{{H}_{3}})]$ is:
(A) Sodium amminechlorobromonitro-N-platinum (II).
(B) Sodium nitrochlorobromoammine-N-platinate (II).
(C) Sodium amminebromochloronitro-N-platinate (II).
(D) Sodium amminebromochloronitro N-platinum (II).

Answer 1

Hint : As we know the IUPAC naming rules of coordination compounds. Using the charges of ligands determine the oxidation state of the metal ion. The IUPAC nomenclature of organic chemistry is a suggested way of naming organic chemical compounds by the International Union of Pure and Applied Chemistry.

Complete Step By Step Answer:
As we know the IUPAC naming rules of coordination compounds. The ligands are named first and the central metal atom is named last. Name the ligand in alphabetical order. Negative ligands are named as ending O. Positively charged ligands have the suffix –ium. Neutral ligands are given their usual name, with some exception. Use Greek prefix di, tri for multiple monodentate ligands and use prefix bis, tris for multiple polydentate ligands. Use the Roman numeral in parentheses to indicate the oxidation state of the metal ion. Use the suffix-ate for the central metal atom if the complex is an anion.
While writing the names of ligands it should be in the following order: neutral, negative, positive. If multiple ligands have the same charge, then they should be named in alphabetical order. If a ligand is having multiple occurrences (monodentate) in that case we use the prefixes like: di, tri, tetra, penta, hexa respectively. For polydentate ligands we use: bis-, tris-, tetrakis-, etc. Anions ends with: ido. Like anion ending with e becomes ato example, sulphate becomes sulphate and becomes ‘ido’, example, cyanide becomes cyanide.
Here the IUPAC name of the complex $Na[PtBrCl(N{{O}_{2}})(N{{H}_{3}})]$ is Sodium amminebromochloronitro-N-platinate (II). Here, the sodium ion is the cation, and the compound ion is the anion. Ammine, bromo, chloro, and nitro-N are among the ligands available here. The nitro group coordinates across the N atom in this case. The ligands' names are arranged in alphabetical order. Platinum has an oxidation state of $+2.$ Within the parenthesis, the oxidation state is written in Roman numerals.
Therefore, the correct answer is option B.

Note :
Remember that if it is required to specify the oxidation state in case of atoms with multiple oxidations states us Roman numerals. End with “cation” or “anion” as separate. Also, if the complex is an anion, then it will end with –ate and its Latin name is to be used except in case of mercury.