Question

The IUPAC name of the following compound is:

Answer 1

oct-1-en-6-yne-4-ol

Answer 2

Step 1: Identify the longest carbon chain.
The compound has 8 carbon atoms, includes an alkene, an alkyne and an alcohol. Thus, the parent is “oct‑”.

Step 2: Numbering the chain.
Numbering from the alkene end gives substituent locants:

• Alkene at C‑1
• Alcohol (–OH) at C‑4
• Alkyne at C‑6

This set of locants (1, 4, 6) is the lowest possible.

Step 3: Assemble the name.
Suffixes are combined as “en” (alkene), “yne” (alkyne), and “ol” (alcohol), and liberally separated by hyphens. The alcohol has the highest priority and appears last.

Final IUPAC name:
oct‑1‑en‑6‑yne‑4‑ol