Question

The IUPAC name of the complex $[Pt{{\left( N{{H}_{3}} \right)}_{2}}Cl\left( N{{H}_{2}}C{{H}_{3}}) \right]Cl$ is:
A. Diamine Chloride(methanamine)platinium(II)chloride
B. Bisamine(methanamine)chloride platinum(II)chloride
C. Diamine Chloride(aminomethane)platinium(II)chloride
D. Diamine(methanamine)chloride platinum(II)chloride

Answer 1

We have to check how many ligands are there in the given complex. We have to find the metal name and find the oxidation state of the metal in the given complex. By considering all these only we can write the IUPAC name of the given coordination complex.

Complete step-by-step answer: - In the question it is given to write the IUPAC name of the given coordination complex.
- The ligands which are present in the given complex are methyl amine ($C{{H}_{3}}N{{H}_{2}}$ ) and amine ($N{{H}_{3}}$ ).
- The number of methyl amine ligands is one and the number of amine ligands are two.
- In the given complex there is one chlorine atom in the inner sphere and one chlorine atom in the outer sphere complex.
- The chlorine which is present in the inner sphere is supposed to be written as chloro and the chlorine which is present in the outer sphere complex is supposed to be named as chloride as per IUPAC.
- There are two amines in the given complex therefore we are supposed to write as diamine in IUPAC name.
- The oxidation state of the platinum in the given complex is
x-1 = 1
x =2
- We have to write the ligands names as per the alphabetic order.
- Therefore the IUPAC name of the given coordination complex is Diamine Chloride(methanamine)platinium(II)chloride.

So, the correct option is A.

Note: We are not supposed to name two chlorine atoms named in the IUPAC name together because one chlorine is present in the inner sphere and the other chlorine atom is present in the outer sphere complex.