Question

The IUPAC name of the complex $[Co{(N{H_3})_2}{({H_2}O)_4}]C{l_3}$ is:
$A)$ Diammine Tetraaqua Cobalt $(III)$ trichloride
$B)$ Diaminetraaquacobalt $(II)$ chloride
$C)$ Tetraaqua Diamine Cobalt $(III)$ trichloride
$D)$ Tetraaqua Diamine Cobalt $(III)$ trichloride
$E)$ tetraaqua diamine cobalt $(II)$ chloride.

Answer 1

The naming of the given compound is done by a set of rules for coordination complexes, in which the one part is cation and the other is anion and the cation is always named before anion.

Complete answer:
-Ligands that go about as anions which end in "- ide" are supplanted with a consummation " $o$ " (e.g., Chloride → Chloro). Anions finishing with "- ite" and "- ate" are supplanted with endings "- ito" and "- ato" individually (e.g., Nitrite → Nitrito, Nitrate → Nitrato).
-Most nonpartisan particles that are ligands convey their typical name. The couple of special cases are the initial four on the outline: ammine, water, carbonyl, and nitrosyl.
-The quantity of ligands present in the complex is shown with the prefixes di, tri, and so forth The special cases are polydentates that have a prefix effectively in their name (en and EDTA-are the most widely recognized).
-When naming the metal community, you should know the conventional metal name and the oxidation state. To show the oxidation state, we utilize Roman numerals inside bracket
The oxidation state of the given compound is $+ 3$ .
Therefore, The IUPAC name given is Diamine Tetra Aqua Cobalt $(III)$ trichloride.
So, the correct option is $A)$ .

Note:
Remember to calculate carefully the charge on metal ions and ligands because they help in finding the naming of the compound and oxidation number of the given compound.