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Question

Chemistry Question on Molecular Orbital Theory

The isoelectronic pair is

A

Cl2O,ICl2−Cl _{2} O , ICl _{2}^{-}

B

ICl2−,ClO2ICl _{2}^{-}, ClO _{2}

C

IF2+,I3−IF _{2}^{+}, I _{3}^{-}

D

ClO2−,ClF2+ClO _{2}^{-}, ClF _{2}^{+}

Answer

ClO2−,ClF2+ClO _{2}^{-}, ClF _{2}^{+}

Explanation

Solution

ClO2−ClO _{2}^{-}and ClF2+ClF _{2}^{+}are isoelectronic species. Number of electrons in ClO2−=17+16+1=34ClO _{2}^{-}=17+16+1=34 electrons Number of electrons in ClF2+ClF _{2}^{+} =17+18−1=34=17+18-1=34 electrons [Number of electrons in Cl=17,O=8,F=9Cl =17, O =8, F =9 ]