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Question: The ionization energy of per mole of hydrogen atom in terms of Rydberg constant (R<sub>H</sub>) is g...

The ionization energy of per mole of hydrogen atom in terms of Rydberg constant (RH) is given by the expression

A

RHhc

B

RHc

C

2 RHhc

D

RH NAhc

Answer

RH NAhc

Explanation

Solution

1λ\frac{1}{\lambda} = RH (1n121n22)\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right)

For ionization of H-atom , n1 = 1 and n2 = 

\ 1λ\frac{1}{\lambda} = RH and IE = NA cλ\frac{c}{\lambda}× h = RH NA hc