Question
Question: The ionization energy of hydrogen atom is 13.6 eV. The third ionization energy of lithium would be –...
The ionization energy of hydrogen atom is 13.6 eV. The third ionization energy of lithium would be –
A
13.6 eV
B
27.2 eV
C
40.8 eV
D
122.4 eV
Answer
122.4 eV
Explanation
Solution
3rd I.E. of Li = I.E. of Li2+
from I.E. of any single electron species
= 13.6 × z2 eV
= 13.6 × 32 eV
= 122.4 eV