Question

The ionization energy of $10$ times ionized sodium atom is

• A. $\frac{13.6}{11}eV$
• B. $\frac{13.6}{{{(11)}^{2}}}eV$
• C. $13.6\times {{(11)}^{2}}eV$
• D. $13.6\,eV$

Answer 1

Answer: (C)

$13.6\times {{(11)}^{2}}eV$

Answer 2

The Bohr model of hydrogen atom can be extended to hydrogen like atoms. Energy of such an atom is given by $E_{n}=-13.6 \frac{Z^{2}}{n^{2}}$ Here, $Z=11$ for $N a$ atom; $10$ electrons are removed already, so it is $10$ limes ionised. For the last electron to be removed, $n=1$ $\therefore$ $E_{n}=\frac{13.6(11)^{2}}{(1)^{2}} \,e V$ or $E_{n}=-13.6 \times(11)^{2}\, e V$