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Question: The ionization constant of a weak electrolyte is \(\text{25 × 1}\text{0}^{\text{-6}}\) while the equ...

The ionization constant of a weak electrolyte is 25 × 10-6\text{25 × 1}\text{0}^{\text{-6}} while the equivalent conductance of its 0.01 M solution is 19.6 S cm2 eq-1.\text{19.6 S c}\text{m}^{2}\text{ e}\text{q}^{\text{-1}}. The equivalent conductance of the electrolyte at infinite dilution (in S cm2eq–1 ) will be

A

250

B

196

C

392

D

384

Answer

392

Explanation

Solution

Ka = 25×10–6 = 19.6 Scm2 eq–1 ,

C = 0.01

Ka = 0.01 × a2

⇒\Rightarrowa = 25×10−610−2\sqrt { \frac { 25 \times 10 ^ { - 6 } } { 10 ^ { - 2 } } }

= 5 × 10–2

a = 5 × 10–2 = 19.6∧eq∘\frac { 19.6 } { \wedge _ { \mathrm { eq } } ^ { \circ } } ⇒\Rightarrow = 19.65×10−2\frac { 19.6 } { 5 \times 10 ^ { - 2 } }= 392 Scm2 eq-1