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Question: The ionization constant of a weak electrolyte is \(25 \times 10^{- 6}\)while the equivalent conducta...

The ionization constant of a weak electrolyte is 25×10−625 \times 10^{- 6}while the equivalent conductance of its 0.01 M solution is 19.6Scm2eq−1.19.6Scm^{2}eq^{- 1}. The equivalent conductance of the

electrolyte at infinite dilution (in Scm2eq−1Scm^{2}eq^{- 1}) will be

A

250

B

196

C

392

D

384

Answer

392

Explanation

Solution

HACC(1−α)\underset{C(1 - \alpha)}{\underset{C}{HA}}⇌ H+0Cα+A−0Cα\underset{C\alpha}{\underset{0}{H^{+}}} + \underset{C\alpha}{\underset{0}{A^{-}}}; K=Cα.CαC(1−α)=Cα21−αK = \frac{C\alpha.C\alpha}{C(1 - \alpha)} = \frac{C\alpha^{2}}{1 - \alpha}≃Cα2C\alpha^{2}

25×10−6=10−2×α225 \times 10^{- 6} = 10^{- 2} \times \alpha^{2} or α=5×10−2\alpha = 5 \times 10^{- 2}

α=ΛcΛ0\alpha = \frac{\Lambda^{c}}{\Lambda^{0}} or Λ0=Λcα=19.65×10−2=392Ω−1cm2.\Lambda^{0} = \frac{\Lambda^{c}}{\alpha} = \frac{19.6}{5 \times 10^{- 2}} = 392\Omega^{- 1}cm^{2}.