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Question: The ionisation potential of mercury is 10.39 volt. To gain energy sufficient enough to ionise mercur...

The ionisation potential of mercury is 10.39 volt. To gain energy sufficient enough to ionise mercury, an electron must travel in an electric field of 1.5 × 106 V m–1 a distance of –

A

10.391.5×(10)6\frac{10.39}{1.5 \times (10)^{6}}m

B

10.39 × 1.5 × 106 m

C

10.39 × 1.6 × 10–19 m

D

10.39×1.6×10–191.5×(10)6\frac{10.39 \times 1.6 \times 10^{–19}}{1.5 \times (10)^{6}} m

Answer

10.391.5×(10)6\frac{10.39}{1.5 \times (10)^{6}}m

Explanation

Solution

E = Vd\frac{V}{d}