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Question

Chemistry Question on Bohr’s Model for Hydrogen Atom

The ionisation potential for He+He^+ is

A

54.4eV54.4\,eV

B

6.8eV6.8\,eV

C

13.6eV13.6\,eV

D

24.5eV24.5\,eV

Answer

54.4eV54.4\,eV

Explanation

Solution

En=13.6n2Z2E_{n} = \frac{-13.6}{n^{2}} Z^{2} E1=13.612×4E_{1 }= \frac{-13.6}{1^{2}}\times 4 =54.4eV= -54.4\, eV Ionisation potential =EE1= E_{\infty} - E_{1} =0(54.4)eV=54.4eV = 0-\left(-54.4\right) \,eV = 54.4\, eV