Question

The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between the 3rd and the 4th orbit is.

• A. 3.40 eV
• B. 1.51 eV
• C. 0.85 eV
• D. 0.66 eV

Answer 1

Answer: (D)

0.66 eV

Answer 2

$E _ { 3 } = - \frac { 13.6 } { 9 } = - 1.51 \mathrm { eV }$ $E_{4} = - \frac{13.6}{16} = - 0.85\mspace{6mu} eV$

$\therefore E_{4} - E_{3} = 0.66\mspace{6mu} eV$