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Chemistry Question on Ionic Equilibrium In Solution

The ionisation constant of ammonium hydroxide is 1.77×10−51.77 \times 10^{-5} at 298 K.298\, K. Hydrolysis constant of ammonium chloride is

A

5.65×10−105.65 \times 10^{-10}

B

6.50×10−126.50 \times 10^{-12}

C

5.65×10−135.65 \times 10^{-13}

D

5.65×10−125.65 \times 10^{-12}

Answer

5.65×10−105.65 \times 10^{-10}

Explanation

Solution

Kh=KwKb=10−141.77×10−5K _{ h }=\frac{ K _{ w }}{ K _{ b }}=\frac{10^{-14}}{1.77 \times 10^{-5}}
=5.65×10−10=5.65 \times 10^{-10}