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Question

Chemistry Question on coordination compounds

The ion which is not tetrahedral in shape is

A

BF4BF _{4}-

B

NH4+NH _{4}{ }^{+}

C

Cu(NH3)42+Cu \left( NH _{3}\right)_{4}^{2+}

D

NiCl42NiCl _{4}^{2-}

Answer

Cu(NH3)42+Cu \left( NH _{3}\right)_{4}^{2+}

Explanation

Solution

[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+} is square planar in shape with Cu2+dsp2Cu^{2+}\, d \, sp^2 -hybridised.