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Question

Chemistry Question on Van Der Waals equation

The inversion temperature for a van der Waals gas is given by:

A

Ti=2aRb{{T}_{i}}=\frac{2a}{Rb}

B

Ti=aRb{{T}_{i}}=\frac{a}{Rb}

C

Ti=a2Rb{{T}_{i}}=\frac{a}{2Rb}

D

Ti=0.5TBoyle{{T}_{i}}=0.5\,{{T}_{Boyle}}

Answer

Ti=2aRb{{T}_{i}}=\frac{2a}{Rb}

Explanation

Solution

Inversion temperature of a van der Waals gas is given by Ti=2aRb=2Tb{{T}_{i}}=\frac{2a}{Rb}=2{{T}_{b}} (where Tb={{T}_{b}}= Boyle temperature)