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Question: The inverse of the proposition \((p\mspace{6mu} \land \sim q) \Rightarrow r\) is...

The inverse of the proposition (p6muq)r(p\mspace{6mu} \land \sim q) \Rightarrow r is

A

r6mupq\sim r \Rightarrow \mspace{6mu}\sim p \vee q020.000

B

pq6mur\sim p \vee q \Rightarrow \mspace{6mu}\sim r

C

rp6muqr \Rightarrow p\mspace{6mu} \land \sim q

D

None of these

Answer

pq6mur\sim p \vee q \Rightarrow \mspace{6mu}\sim r

Explanation

Solution

Inverse of pqp \Rightarrow q is p6muq\sim p \Rightarrow \mspace{6mu}\sim q

∴ inverse of (p6muq)r(p\mspace{6mu} \land \sim q) \Rightarrow r is

(p6muq)6mur\sim(p\mspace{6mu} \land \sim q) \Rightarrow \mspace{6mu}\sim r i.e. (pq)6mur(\sim p \vee q) \Rightarrow \mspace{6mu}\sim r.