Question
Mathematics Question on mathematical reasoning
The inverse of the proposition (p∧∼q)→r is
A
(∼r)→(∼p)∨q
B
(∼p)∨q→(∼r)
C
r→p∧(∼q)
D
(∼p)∨(∼q)→r
Answer
(∼p)∨q→(∼r)
Explanation
Solution
Given proposition is
(p∧∼q)→r...(i)
Inverse of E (i) is
∼(p∧∼q)→∼r
≡∼p∨q→∼r
≡(∼p)∨q→(∼r)