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Question

Mathematics Question on mathematical reasoning

The inverse of the proposition (pq)r(p \wedge \sim q)\rightarrow r is

A

(r)(p)q(\sim\,r) \rightarrow(\sim p) \vee q

B

(p)q(r)(\sim p) \vee q \rightarrow (\sim r)

C

rp(q)r \rightarrow p \wedge(\sim q)

D

(p)(q)r(\sim p)\vee(\sim q) \rightarrow r

Answer

(p)q(r)(\sim p) \vee q \rightarrow (\sim r)

Explanation

Solution

Given proposition is
(pq)r...(i)(p \wedge \sim q) \rightarrow r\,\,\,\,\,\,...(i)
Inverse of E (i) is
(pq)r\sim(p \wedge \sim q) \rightarrow \sim r
pqr\equiv \sim p \vee q \rightarrow \sim r
(p)q(r)\equiv(\sim p) \vee q \rightarrow(\sim r)