The inverse of a function: (x=\sqrt{3y+9}) is | Mathematics | SolveeIt | Solveeit

Today, August 24

Question

The inverse of a function: $x=\sqrt{3y+9}$ is

A

$x^2-\frac{3}{2}$

B

$\frac{1}{3}x^2$

C

-3x2+1

D

$\frac{1}{3}x^2$ -3

Answer

$\frac{1}{3}x^2$ -3

Explanation

Solution

The correct option is(D): $\frac{1}{3}x^2$ -3