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Question: The internal resistances of two cells shown are \(0.3 \Omega\). If \(R = 0.2 \Omega\), the potential...

The internal resistances of two cells shown are 0.3Ω0.3 \Omega. If R=0.2ΩR = 0.2 \Omega, the potential difference across the cell

A

B will be zero

B

A will be zero

C

A and B will be 2V

D

A will be and B will be

Answer

B will be zero

Explanation

Solution

Applying Kirchhoff law

(2+2)=(0.1+0.3+0.2)i( 2 + 2 ) = ( 0.1 + 0.3 + 0.2 ) ii=203Ai = \frac { 20 } { 3 } A

Hence potential difference across A

=20.1×203=43V= 2 - 0.1 \times \frac { 20 } { 3 } = \frac { 4 } { 3 } V (less than 2V)

Potential difference across

B=20.3×203=0B = 2 - 0.3 \times \frac { 20 } { 3 } = 0