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Question

Question: The internal resistance of a primary cell is 4 ohm. It generates a current of 0.2 amp in an external...

The internal resistance of a primary cell is 4 ohm. It generates a current of 0.2 amp in an external resistance of 21 ohm. The rate at which chemical energy is consumed in providing the current is

A

0.42J/s0.42J/s

B

0.84J/s0.84J/s

C

5J/s5J/s

D

1J/s1J/s

Answer

1J/s1J/s

Explanation

Solution

Ht=i2R\frac{H}{t} = i^{2}R. Here total R=(21+4)=25ΩR = (21 + 4) = 25\Omega

⇒ Rate of energy consumed =0.2×0.2×25=1J/s= 0.2 \times 0.2 \times 25 = 1J/s