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Question

Physics Question on Current electricity

The internal resistance of a cell of e.m.f. 2 V is 0.1Ω0.1\, \Omega It is connected to a resistance of 3.9Ω3.9\, \Omega. The voltage across the cell will be

A

1.95 V

B

1.9 V

C

0.5 V

D

2 V

Answer

1.95 V

Explanation

Solution

i=24=0.5i=\frac{2}{4}=0.5 Ampere
V=εirV= \, \varepsilon -ir
or V=20.5×0.1=1.95VV = 2-0.5 \times 0.1= 1.95\, V