Question

The internal energy of one mole of ideal gas is

• A. 3/2 RT
• B. 1/2 kT
• C. 1/2 RT
• D. 3/2 kT

Answer 1

Answer: (A)

3/2 RT

Answer 2

K.E. = $\frac{1}{2} \, mv^2 = \frac{3}{2}$ RT (for 1 molecule) For n moles K.E. = $\frac{3}{2} KT$ (k = Boltzmann's constant)