Question
Question: The internal energy change in a system that has absorbed \(2{\text{ }}kcal\) of a heat and done \(50...
The internal energy change in a system that has absorbed 2 kcal of a heat and done 500j of work is:
(A) 7900j
(B) 8900j
(C) 3400j
(D) 5400j
Solution
The First Law of Thermodynamics states that energy can be converted from one form to another with the interaction of heat, work and internal energy, but it can not be created nor destroyed, under any circumstances. when energy passes into or out of a system (as work, heat, or matter), the system's internal energy changes in accord with the law of conservation of energy.
ΔH=ΔU+W
Complete step by step answer:
Mathematically, this is represented as
ΔH=ΔU+W
where
ΔH=heat exchanged between a system and its surroundings
ΔU=total change in internal energy of a system
W=work done by or on the system
Given,
ΔH=2kcal
As we know that 1 cal=4.184j so,
ΔH=2kcal
⇒ΔH=2×1000×4.184j
⇒ΔH=8368j
⇒W=500j
Using the first thermodynamic law equation
ΔH=ΔU+W
Substitute the value of △H and W in the above equation
8368j=ΔU+500j
⇒ΔU=8368j−500j
⇒ΔU=7868j
So now we check the given option and select the approximate value nearest the answer. After checking the options we can say the value which is given in option (A) 7900j is nearest to the 7868j.
Note:
The internal energy of a system is identified with the random, disordered motion of molecules; the total (internal) energy in a system includes potential and kinetic energy. This is contrast to external energy which is a function of the sample with respect to the outside environment (e.g. kinetic energy if the sample is moving or potential energy if the sample is at a height from the ground etc).
Internal energy includes energy on a microscopic scale
It is the sum of all the microscopic energies such as:
translational kinetic energy.
vibrational and rotational kinetic energy.
potential energy from intermolecular forces.