Question

The interionic distance for cesium chloride crystal will be

• A. $a$
• B. $a/2$
• C. $\sqrt{3} a / 2$
• D. $2a / \sqrt{3}$

Answer 1

Answer: (C)

$\sqrt{3} a / 2$

Answer 2

As $CsCl$ is body-centred, $d = \sqrt{3} a / 2$