Question

The interionic distance for cesium chloride crystal will be.

• A. a
• B. $\frac{a}{2}$
• C. $\frac{\sqrt{3}a}{2}$
• D. $\frac{2a}{\sqrt{3}}$

Answer 1

Answer: (C)

$\frac{\sqrt{3}a}{2}$

Answer 2

As $CsCl$ is body-centred,