Question

The intercepts of the plane $5x - 3y + 6z = 60$on the co-ordinate axes are

• A. $(10,20, - 10)$
• B. (10, – 20, 12)
• C. (12, – 20, 10)
• D. (12, 20, – 10)

Answer 1

Answer: (C)

(12, – 20, 10)

Answer 2

$\frac { 5 x } { 60 } - \frac { 3 y } { 60 } + \frac { 6 z } { 60 } = 1$ ⇒ $\frac { x } { 12 } - \frac { y } { 20 } + \frac { z } { 10 } = 1$

Hence, the intercepts are (12, –20, 10).