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Question: The interatomic distance for a metal is \(3 \times 10 ^ { - 10 } \mathrm {~m}\). If the interatomic ...

The interatomic distance for a metal is 3×10−10 m3 \times 10 ^ { - 10 } \mathrm {~m}. If the interatomic force constant is , then the

Young's modulus in N/m2N / m ^ { 2 } will be

A

1.2×10111.2 \times 10 ^ { 11 }

B

4.2×10114.2 \times 10 ^ { 11 }

C

10.8×10−1910.8 \times 10 ^ { - 19 }

D

2.4×10102.4 \times 10 ^ { 10 }

Answer

1.2×10111.2 \times 10 ^ { 11 }

Explanation

Solution

Y=3.6×10−9 N/A˚3×10−10 mY = \frac { 3.6 \times 10 ^ { - 9 } \mathrm {~N} / \AA } { 3 \times 10 ^ { - 10 } \mathrm {~m} } =1.2×1011 N/m2= 1.2 \times 10 ^ { 11 } \mathrm {~N} / \mathrm { m } ^ { 2 }