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Question: The intensity of electric field required to balance a proton of mass \(1.7 \times 10^{- 27}kg\) and ...

The intensity of electric field required to balance a proton of mass 1.7×10−27kg1.7 \times 10^{- 27}kg and charge1.6×10−19C1.6 \times 10^{- 19}C is nearly

A

1×10−7 6muV/m1 \times 10^{- 7}\mspace{6mu} V/m

B

1×10−5 6muV/m1 \times 10^{- 5}\mspace{6mu} V/m

C

1×107 6muV/m1 \times 10^{7}\mspace{6mu} V/m

D

1×105 6muV/m1 \times 10^{5}\mspace{6mu} V/m

Answer

1×10−7 6muV/m1 \times 10^{- 7}\mspace{6mu} V/m

Explanation

Solution

Since qE = mg or E=mgq=1.7×10−27×9.81.6×10−19E = \frac{mg}{q} = \frac{1.7 \times 10^{- 27} \times 9.8}{1.6 \times 10^{- 19}}

= 10.0 × 10–8 = 1 × 10–7 V/m