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Question

Question: The integrating factor of the differential equation \(\frac{dy}{dx} + \frac{1}{x}y = 3x\) is...

The integrating factor of the differential equation dydx+1xy=3x\frac{dy}{dx} + \frac{1}{x}y = 3x is

A

x

B

In x

C

0

D

1

Answer

x

Explanation

Solution

The given differential equation is dydx+1x=3x\frac{dy}{dx} + \frac{1}{x} = 3x

Here, P=1xP = \frac{1}{x} and Q = 3x

I.F. epdx=e1xdx=elogx=xe^{\int_{}^{}{pdx}} = e^{\int_{}^{}{\frac{1}{x}dx}} = e^{\log x} = x