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Question

Mathematics Question on Definite Integral

The integral 01x(1x)ndx\int_0^1x(1-x)^n dx is equal to :

A

1(n+2)(n+3)\frac{1}{(n+2)(n+3)}

B

1(n+1)(n+2)\frac{1}{(n+1)(n+2)}

C

1n(n+1)\frac{1}{n(n+1)}

D

1(n1)(n2)\frac{1}{(n-1)(n-2)}

Answer

1(n+1)(n+2)\frac{1}{(n+1)(n+2)}

Explanation

Solution

The correct option is (B):

1(n+1)(n+2)\frac{1}{(n+1)(n+2)}