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Question

Mathematics Question on integral

The integral ∫3lx3∫_3^lx^3 log(x) dx equals

A

344[log(3)]\frac{3^4}{4} [log(3)]

B

344[log(3)−14]\frac{3^4}{4} [log(3)-\frac{1}{4}]

C

344[log(3)]+116\frac{3^4}{4} [log(3)]+\frac{1}{16}

D

344[log(3)=14]+116\frac{3^4}{4} [log(3)=\frac{1}{4}]+\frac{1}{16}

Answer

344[log(3)=14]+116\frac{3^4}{4} [log(3)=\frac{1}{4}]+\frac{1}{16}

Explanation

Solution

The correct option is(D): 344[log(3)=14]+116\frac{3^4}{4} [log(3)=\frac{1}{4}]+\frac{1}{16}