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Question

Physics Question on Electric charges and fields

The insulation property of air breakdown is 3×106V/m3 \times 10^6 V/m. Maximum charge in coulomb that can be given to a sphere of radius 10 cm is approximately

A

2μC2 \, \mu C

B

4.3μC4.3 \, \mu C

C

3.3μC3.3 \, \mu C

D

5.4μC5.4 \, \mu C

Answer

3.3μC3.3 \, \mu C

Explanation

Solution

Here, Emax=3×106Vm,E_{max} = 3\times10^{6} V m ,
r=10cm=0.1mr = 10 cm = 0.1 m
As E=14πε0qr2E = \frac{1}{4\pi \varepsilon_{0}} \frac{q}{r^{2}}
qmax=Emax×4πε0r2\therefore \, \, q_{max } = E_{max} \times 4\pi \varepsilon_{0}r^{2}
=3×106×(0.1)29×109=3.3μC\, \, \, \, \, \, \, \, \, \, \, = \frac{3\times 10^{6} \times \left(0.1\right)^{2}}{9\times 10^{9}} = 3.3 \mu C