Question

The instantaneous voltage of a $50\,Hz$ generator giving peak voltage as $300\,V$. The generator equation for this voltage is

• A. $V = 50 \, \sin \, 300\pi t$
• B. $V = 300 \, \sin \, 100\pi t$
• C. $V = 6 \, \sin \, 100\pi t$
• D. $V = 50 \, \sin \, 100\pi t$

Answer 1

Answer: (B)

$V = 300 \, \sin \, 100\pi t$

Answer 2

Here, frequency of generator, $v = 50\, {Hz}$
peak voltage, $V_0 = 300\, V$
Instantaneous voltage of the generator,
$V = V_0 \sin\, \omega t = V_0 \sin\, 2\pi vt = 300 \, \sin \, 100 \pi t$