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Question: The input resistance of transistor is 1000 \(\Omega\)on charging its base current by 10\(\mu A,\) th...

The input resistance of transistor is 1000 Ω\Omegaon charging its base current by 10μA,\mu A, the collector current increases by 2 mA if a load resistance is 5 kΩk\Omega is used in the circuit, the voltage gain of the amplifier is

A

100

B

500

C

1000

D

1500

Answer

1000

Explanation

Solution

: current gain, β=(ΔICΔIB)VCE\beta = \left( \frac{\Delta I_{C}}{\Delta I_{B}} \right)_{V_{CE}}

And voltage gain, AV=βRoutRinA_{V} = \beta\frac{R_{out}}{R_{in}}

Here, AV=200×5×1031000=1000A_{V} = \frac{200 \times 5 \times 10^{3}}{1000} = 1000