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Question

Question: The initial velocity of the particle is \(10 \mathrm {~m} / \mathrm { sec }\) and its retardation ...

The initial velocity of the particle is 10 m/sec10 \mathrm {~m} / \mathrm { sec } and its retardation is 2m/sec22 m / \sec ^ { 2 } . The distance moved by the particle in 5 th second of its motion is

A

1m1 m

B

19 m

C

50 m

D

75 m

Answer

1m1 m

Explanation

Solution

Sn=ua2(2n1)S _ { n } = u - \frac { a } { 2 } ( 2 n - 1 ) =1022(2×51)=1= 10 - \frac { 2 } { 2 } ( 2 \times 5 - 1 ) = 1 meter