Question
Question: The initial velocity of the particle is \(10 \mathrm {~m} / \mathrm { sec }\) and its retardation ...
The initial velocity of the particle is 10 m/sec and its retardation is 2m/sec2 . The distance moved by the particle in 5 th second of its motion is
A
1m
B
19 m
C
50 m
D
75 m
Answer
1m
Explanation
Solution
Sn=u−2a(2n−1) =10−22(2×5−1)=1 meter