Solveeit Logo

Question

Physics Question on projectile motion

The initial speed of a projectile fired from ground is uu At the highest point during its motion, the speed of projectile is 32u\frac{\sqrt{3}}{2} u The time of flight of the projectile is :

A

2ug\frac{2 u }{ g }

B

u2g\frac{ u }{2 g }

C

ug\frac{ u }{ g }

D

3ug\frac{\sqrt{3} u}{g}

Answer

ug\frac{ u }{ g }

Explanation

Solution

u cosθ=3u2u\ cosθ=\frac{\sqrt{3}​u}{2}
cosθ=32⇒cosθ=\frac{\sqrt{3}}{2}
θ=30⇒θ=30^∘
T=2usin30g=ugT=\frac{2usin30^∘}{g}​=\frac{u}{g}
Correct answer is option (b)