Question

The increasing order of reducing power of the halogen acids is

• A. HF < HCl < HBr < HI
• B. HI < HBr < HCl < HF
• C. HBr < HCl < HF < HI
• D. HCl < HBr < HF < HI

Answer 1

Answer: (A)

HF < HCl < HBr < HI

Answer 2

As the size of halogen atom increases, the bond strength of H-X bond decreases so tendency to give hydrogen increases resulting in increase in the reducing power. So increasing order is HF < HCl < HBr < HI