Question

The increasing order of reactivity in the $S_{N}{2}$ hydrolysis of the following alkylbromides is (1) $tert$-Butyl bromide (2) Methyl bromide (3) $sec$-Butyl bromide (4) $n$ - Propyl bromide

• A. $ (1)
• B. $ (2)
• C. $ (1)
• D. $ (2)

Answer 1

Answer: (A)

$ (1)

Answer 2

Reactivity order in $S_{N}2$ reaction will be
$1^{\circ}>\, 2^{\circ}>\,3^{\circ}$
More bulky substrates are least reactive in $S_{N}2$ reactions

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Therefore, order of reactivity is
$(1)