Question

The increasing order of energies of various molecular orbitals of $N_2$ is given below: $\sigma 1s < \sigma^* 1s

• A. $C_2$
• B. $B_2$
• C. $O_2$
• D. $Be_2$

Answer 1

Answer: (C)

$O_2$

Answer 2

For all elements which have atomic number more than $7$ (beyond nitrogen) the energy of $\sigma 2p_z$ is lower than $\pi 2p_x$ and $\pi 2p_y$ -orbitals.