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Question: The increasing order of energies of various molecular orbitals of \(N_{2}\)is given below: \[\sigma...

The increasing order of energies of various molecular orbitals of N2N_{2}is given below:

σ1s<σ1s<σ2s<σ2s<π2px\sigma 1s < \sigma*1s < \sigma 2s < \sigma*2s < \pi 2p_{x}

=π2py<σ2pz<π2px=π2py<σ2pz\pi 2p_{y} < \sigma 2p_{z} < \pi*2p_{x} = \pi*2p_{y} < \sigma^{*}2p_{z}

The above sequence is not true for the molecule

A

C2C_{2}

B

B2B_{2}

C

O2O_{2}

D

Be2Be_{2}

Answer

O2O_{2}

Explanation

Solution

: For all elements which have atomic number more than 7 (beyond nitrogen) the energy of σ2pz\sigma 2p_{z}is lower than π2px\pi 2p_{x}and π2py\pi 2p_{y}- orbitals.