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Question

Physics Question on communication systems

The increase in the height of the tower of height 200m200\,m to get its coverage range tripled is

A

800 m

B

1600 m

C

900 m

D

700 m

Answer

1600 m

Explanation

Solution

Coverage range, d=2Rhd = \sqrt{2Rh}
where R is the radius of the earth and h is the height of a tower .
dhd \propto\sqrt{h}
d3d=hh\therefore \:\:\:\:\:\frac{d}{3d} = \sqrt{\frac{h}{h}} or 19=hh\frac{1}{9} = \frac{h}{h'}

or h=9h=9×200m=1800mh' = 9h = 9 \times 200 \, m = 1800 \, m
Increase in the height of the tower
=hh=1800m200m=1600m= h' -h = 1800 \, m - 200\, m = 1600 \, m