Question

The increase in pressure required to decrease the $200 \,L$ volume of a liquid by $0.008\%$ in $kPa$ is (Bulk modulus of the liquid $= 2100 \,MPa$ is)

• A. $8.4$
• B. $84$
• C. $92.4$
• D. $168$

Answer 1

Answer: (B)

$84$

Answer 2

Bulk modulus $K=\frac{\Delta p}{\Delta V} \cdot V$
$\Delta p =\frac{K \Delta V}{V}$
$\Delta p =\frac{2100 \times 10^{6} \times 0.008}{200}$
$=84 \,kpa$