Question
Question: The incorrect statement for 14g CO is: (A) It occupies 2.24L at NTP. (B) It corresponds to 0.5 m...
The incorrect statement for 14g CO is:
(A) It occupies 2.24L at NTP.
(B) It corresponds to 0.5 moles of CO.
(C) It corresponds to the same moles of CO and N2.
(D) It corresponds to 3.01×1023 molecules of CO.
Solution
CO also known as carbon monoxide is a harmful toxic gas. It is one of the major constituents of pollutant gases. It is released if the fuel is burnt in insufficient amounts of oxygen. CO also causes carbon monoxide poisoning in humans if inhaled in excess.
The approach to answer this question is by calculating the moles of CO present in 14g.
Complete answer:
Let’s look at the solution to this question:
First, we will calculate the number of moles in 14g of CO.
Given mass of CO = 14g
Molar mass of CO = 28g
MolesofCO=MolarmassGivenMass
MolesofCO=2814=0.5
So, the number of moles present in 14g of CO is 0.5
So, the given statement in option (B) is correct.
Now, we will calculate the moles in 14g of N2
Given mass of N2= 14g
Molar mass of N2= 28g
MolesofN2=MolarmassGivenMass
MolesofN2=2814=0.5
So, the number of moles present in CO and N2 is the same.
Hence, the given statement in option (C) is correct.
Now, we will calculate the number of molecules present in 14 grams of N2
Numberofmolecules=Moles×Avogadronumber
NumberofmoleculesofN2=0.5×6.02×1023=3.01×1023
So, the number of molecules present in 14g of N2 is 3.01×1023.
So, the statement given in option (D) is correct.
Now, we know that 1 mole of a gas occupies 22.4L at NTP,
Therefore, 0.5 moles will occupy 0.5×22.4=11.2L
So, the statement given in option (A) is incorrect.
Hence, the answer for the given question is option (A).
Note: At NTP the volume occupied by an ideal gas is 22.4L. This is true for all gases. This happens because the volume of a gas molecule is considered negligible according to the kinetic theory of gases.