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Chemistry Question on Chemical Kinetics

The incorrect equation for Arrhenius equation for activation energy is:

A

In  k=In  A−EaRTIneIn\;k= In\;A-\frac{Ea}{RT}Ine

B

log⁡k=−Ea2.303R1T×log⁡A\log k=-\frac{Ea}{2.303R}\frac{1}{T\times\log A}

C

log⁡k2k1=Ea2.303R(T2−T1T1T2)\log \frac{k_2}{k_1}=\frac{Ea}{2.303R}(\frac{T_2-T_1}{T_1T_2})

D

log⁡k=−Ea2.303R×1T+log⁡A\log k=-\frac{Ea}{2.303R}\times \frac{1}{T}+\log A

Answer

log⁡k=−Ea2.303R1T×log⁡A\log k=-\frac{Ea}{2.303R}\frac{1}{T\times\log A}

Explanation

Solution

The correct option is (B) : log⁡k=−Ea2.303R1T×log⁡A\log k=-\frac{Ea}{2.303R}\frac{1}{T\times\log A}