Question

The incentre of triangle formed by the lines x = 0, y = 0 and 3x + 4y = 12 is-

• A. $\left( \frac{1}{2},\frac{1}{2} \right)$
• B. (1, 1)
• C. $\left( 1,\frac{1}{2} \right)$
• D. $\left( \frac{11}{2},1 \right)$

Answer 1

Answer: (B)

(1, 1)

Answer 2

AB = c = 4; BC = a = 5

CA = b = 3

Incentre $\left( \frac{ax_{1} + bx_{2} + cx_{3}}{a + b + c},\frac{ay_{1} + by_{2} + cy_{3}}{a + b + c} \right)$

$\left( \frac{5(0) + 3(4) + 4(0)}{5 + 3 + 4},\frac{5(0) + 3(0) + 4(3)}{5 + 3 + 4} \right)$

(1, 1)