Question

The incentre of the triangle formed by (0, 0), (5,12), (16, 12) is.

• A. (7,9)
• B. (9,7)
• C. (–9, 7)
• D. (–7,9)

Answer 1

Answer: (A)

(7,9)

Answer 2

Obviously $a = 11 , b = 20 , c = 13$

Hence incentre is

$\left( \frac { 11 \times 0 + 20 \times 5 + 13 \times 16 } { 11 + 20 + 13 } , \frac { 11 \times 0 + 20 \times 12 + 13 \times 12 } { 11 + 20 + 13 } \right)$

i.e. (7, 9).