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Question

Physics Question on LCR Circuit

The impedance of a circuit, when a resistance R and an inductor of inductance L are connected in series in an AC circuit of frequency f, is

A

R+2π2f2L2\sqrt{ R + 2 \pi^2 \, f^2 \, L^2 }

B

R+4π2f2L2\sqrt{ R + 4 \pi^2 \, f^2 \, L^2 }

C

R2+4π2f2L2\sqrt{ R^2 + 4 \pi^2 \, f^2 \, L^2 }

D

R2+2π2f2L2\sqrt{ R^2 + 2 \pi^2 \, f^2 \, L^2 }

Answer

R2+4π2f2L2\sqrt{ R^2 + 4 \pi^2 \, f^2 \, L^2 }

Explanation

Solution

In L-R circuit,
Impedance Z = R2+XL2\sqrt{ R^2 + X_L^2 }
Here, XL=ωL=2πfLX_L = \omega L = 2 \pi f L
Z=R2+4π2f2L2\therefore Z = \sqrt{ R^2 + 4 \pi^2 f^2 \, L^2 }