Question

The hydrolysis of an ester was carried out separately with 0.05 (N) HCl and 0.05 (N) H₂SO₄. Therefore which of the following is true?

• A. K_HCl>$K_{H_{2}SO_{4}}$
• B. $K_{H_{2}SO_{4}}$>K_HCl
• C. $K_{H_{2}SO_{4}}$ = 2 K_HCl
• D. $K_{H_{2}SO_{4}}$= K_HCl

Answer 1

Answer: (A)

K_HCl>$K_{H_{2}SO_{4}}$

Answer 2

The ester hydrolysis is pseudo first order reaction where rate constant is proportional to the concentration of H⁺. The 0.05 (N) HCl produces greater amount of H⁺ than the 0.05 (N) H₂SO₄. Hence K_HCl >$K_{H_{2}SO_{4}}$